72t-16t^2=0

Solution for 72t-16t^2=0 equation:

72t-16t^2=0

a = -16; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-16)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-16}=\frac{-144}{-32}
=4+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-16}=\frac{0}{-32}
=0
$